1/3^3-2t^2+3t-5t=3

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Solution for 1/3^3-2t^2+3t-5t=3 equation: 


t in (-oo:+oo)

3*t-(2*t^2)-(5*t)+1/(3^3) = 3 // - 3

3*t-(2*t^2)-(5*t)+1/(3^3)-3 = 0

3*t-2*t^2-5*t+1/(3^3)-3 = 0

-2*t^2-2*t-80/27 = 0

DELTA = (-2)^2-(-80/27*(-2)*4)

DELTA = -532/27

DELTA < 0

t belongs to the empty set

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